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Solution of task 20.6.1 from the collection of Kepe OE
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Uploaded: 19.10.2017
Content: 20.6.1.jpg 30,07 kB
Refunds: 0
Uploaded: 19.10.2017
Content: 20.6.1.jpg 30,07 kB
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20.6.1
The kinetic energy of the system is T = 0.25x12 + 0.25 (x12 + x1x2 + x22). From the differential equation of motion of the system corresponding to the generalized coordinate x2, determine the acceleration x2 at the time when the acceleration is x1 = 5 m / s2, and the generalized force Qx2 = 2.5 N. (Answer 2.5)
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